448B - Suffix Structures - CodeForces Solution

implementation strings *1400

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Python Code: 



st = str(input())
en = str(input())

dst = [0]*26
den = [0]*26
for i in range(len(st)):
    dst[ord(st[i])-97] += 1
for i in range(len(en)):
    den[ord(en[i])-97] += 1

if len(en) > len(st):
    print("need tree")
elif len(en) == len(st):
    if dst != den:
        print("need tree")
    else:
        print("array")
else:
    p1,p2 = 0,0
    flag = False
    while p2 < len(st):
        if st[p2] == en[p1]:
            if p1 == len(en)-1:
                flag = True
                break
            p1 += 1
        p2 += 1
    if flag:
        print("automaton")
    else:
        flag = True
        for i in range(26):
            if den[i] > dst[i]:
                print("need tree")
                flag = False
                break
        if flag:
            print("both")

C++ Code: 

#include <bits/stdc++.h>

using namespace std;

typedef unsigned long long ULL;

bool is_only_automaton(const string &s, const string &t) {
    size_t j = -1;
    for (int i = 0; i < t.size(); i++) {
        j = s.find_first_of(t[i], j+1);
        if (j == string::npos) {
            return false;
        }
    }
    return true;
}

int main() {
    string s;
    string t;

    cin>>s;
    cin>>t;
    string ret = "need tree";

    assert(s != t);

    if (s.size() == t.size()) {
        sort(s.begin(), s.end());
        sort(t.begin(), t.end());

        if (s == t) {
            ret = std::move("array");
        }
    }
    else if (is_only_automaton(s, t)) {
        ret = std::move("automaton");
    }
    else {
        sort(s.begin(), s.end());
        sort(t.begin(), t.end());
        if (is_only_automaton(s, t)) {
            ret = std::move("both");
        }
    }

    cout<<ret<<endl;

    return 0;
}


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